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In triangle ABC , write sin …

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In triangle ABC , write sin A+B/2in terms of angle C
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Nitish Vishwakarma 6 years, 3 months ago

We know that in triangle ABC Angle (A + B + C) = 180 Transfer angle on right side, Angle(A+B) = 180- Angle C Dividing 2 on both side , we get Angle(A+B)/2 = 90 - Angle C/2 Multiply sin on both side sin A+B/2 = sin(90-C/2) sin A + B/2 = cos C/2
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