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For what value of p , are (2p-1) , 7 and 11p/2 three consecutive term of an AP

Posted by #Army #Bts 6 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

#Army #Bts 6 years, 3 months ago

Thank you so much ?

0Thank You

Parul Ailawadi 6 years, 3 months ago

d=7-(2p-1)=7-2p+1=8-2p d=(11p/2)-7 =(11p-14)/2 Therefore, 8-2p=(11p-14)/2 16-4p=11p-14 16+14=11p+4p 30=15p 30/15=p p=2

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CBSE > Class 10 > Mathematics