Find the area of the segment …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Sachin Kumar 6 years, 3 months ago
- 3 answers
Yogita Ingle 6 years, 3 months ago
In ∆AOB, draw a perpendicular line from O which intersect AB at M.
In ∆AOM, angle AMO = 90
angle OAM = 30
cos 30 = AM/AO
√3/2 = AM/21
AM = 21×√3/2
AB = 2(AM)
=2(21×√3/2)
=21√3
{tex}OM^2 = AO^2-AM^2{/tex}
{tex}=21^2-(21√3/2)^2{/tex}
=441-330.51
=110.48
OM =√110.48
OM =10.51
OM = 10.51cm
Area of ∆AOM = 1/2 AB × OM
=1/2 ×21√3 ×10.51
=191.14cm^2
Area of sector AOBY = 120πr^2/360
=120×21×21×22/2520
=462cm^2
Area of segment AYB = Area of sector OAYB -Area of∆OAB
=462-191.14
=270.86
Area of segment AYB is 270.86cm2.
Test
Related Questions
Posted by Kanika . 4 months, 2 weeks ago
- 1 answers
Posted by Hari Anand 9 months, 3 weeks ago
- 0 answers
Posted by Lakshay Kumar 1 year, 4 months ago
- 0 answers
Posted by Vanshika Bhatnagar 1 year, 8 months ago
- 2 answers
Posted by Parinith Gowda Ms 7 months ago
- 0 answers
Posted by Parinith Gowda Ms 7 months ago
- 1 answers
Posted by Sahil Sahil 1 year, 8 months ago
- 2 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Arpit Maurya 6 years, 3 months ago
0Thank You