For some a and b HCF …

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Yogita Ingle 6 years, 3 months ago
HCF of 210 and 55
255= 55×3+45...(1)
55=45×1+10...(2)
45=10×4+5...(3)
10=5×2+0. remainder =0
HCF of 210 and 55 =5
NOW,from (3) we get,
45=10×4+5
45-10×4=5
45-(55-45)×4 =5 ....(from 2)
45-55×4+45×4=5
(210-55×3)5-55×4=5 ...(from 1)
210×5-55×15-55×4=5
5=210×5-55×19=210A+55B
therefore,
a=5 and b= -19
1Thank You