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Find largest no which divide 398 ,436, and 542 leaving remainder 7 ,11 and 15 resp

Posted by Alok Dubey 6 years, 3 months ago

CBSE > Class 10 > Mathematics

2 answers

Yogita Ingle 6 years, 3 months ago

On dividing 398 by the required number, there is a remainder of 7. This means that 398 7 = 391 is exactly divisible by the required number. Similarly, 436 -11 = 425 and 542 15 = 527 are exactly divisible by the required number.
The HCF of two positive integers is the largest positive integer that divides both the integers.
So, the required number will be the HCF of 391, 425 and 527. And that can be found by using Euclids division algorithm.
425 = 391 x 1 + 34
391 = 34 x 11 + 17
34 = 17 x 2 + 0
Thus, HCF = 17
Hence, the required number is 17.

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Varsha Narwariya 6 years, 3 months ago

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