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Sides of atriangle a, b, c. If s-a=4cm, s-b=8, s-c=12 then find the value of a, b, c.

Posted by Jyoti Bondu 4 years, 10 months ago

CBSE > Class 09 > Mathematics

2 answers

Vikas Sharma 4 years, 10 months ago

Value of a = 20 , b = 16 and c =12.

0Thank You

Gaurav Seth 4 years, 10 months ago

If a, b, c are sides of triangle then
s=(a+b+c)/2
Given:

s-a=4 cm

s-b=8 cm

s-c=12 cm

Adding these we get

s+s+s-a-b-c = 24

3s-(a+b+c) =24

3s-2s = 24

s = 24

Now,

s-a=4

24 - a =4

a = 24 - 4 = 20 cm

s-b=8

24 - b = 8

b = 24 - 8 = 16 cm

s - c = 12

24 - c = 12

c = 24 -12 = 12 cm

3Thank You

ANSWER

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CBSE > Class 09 > Mathematics