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For the value of x .if the distance between the points A(0,0)&B(x,-4) is 5 units?

Posted by Laxman Laxman 5 years, 11 months ago

CBSE > Class 10 > Mathematics

2 answers

Swastik Shukla 5 years, 11 months ago

By distance formula √(x2-x1)square+(y2-y1)square is equal to distance between two coordinate By appling this formula we find the value of x become distance 5 units so; √(x-0)square+(-4-0)square = 5 units √X square+16=5 Squaring both side we get X square + 16 = 25 X square= 25-16 X square=9 X=√9 X=3 ?

Yogita Ingle 5 years, 11 months ago

The formula used to find the distance between two points is

{tex}d = \sqrt{(x2-x1)^{2}+(y2-y1)^{2} } Where,d = distance = 5\\(x1, y1) = First set of points, i.e A= (0,0)\\(x2, y2) = Second set of points i.e B= (x,-4)d = \sqrt{(x2-x1)^{2}+(y2-y1)^{2} } \\ 5 = \sqrt{(x-0)^{2}+(-4-0)^{2} } \\\\5 = \sqrt{(x)^{2}+(-4)^{2} }\\\\Squaring both sides\\\\25 = x^{2} + 16\\\\25-16 = x^{2}\\\\9 = x^{2}\\\\x = 3{/tex}

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