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Write the HCF of 52 and …

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Write the HCF of 52 and 117 in the form of 52m +117n

Posted by Asit Chakrabortty 5 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Yogita Ingle 5 years, 11 months ago

Let us find HCF of 52 and 117 by Euclid's division algorithm.
Since 117>52
117 = 52 × 2 + 13
52 = 13 × 4 + 0
Therefore HCF (52, 117) = 13

Now, 13 = 52×(-2) + 117×1
13 = 52x + 117y where X = -2 and y = 1

1Thank You

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CBSE > Class 10 > Mathematics