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1+cosA+sinA÷1+cosA-sinA=1+sinA÷cosA

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1+cosA+sinA÷1+cosA-sinA=1+sinA÷cosA

    • Posted by Raj Varshney 5 years, 11 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Vijay Rathore??? 5 years, 11 months ago

    LHS= (1+cosA+sinA)(1+cosA+sinA) ÷ (1+cosA-sinA)(1+cosA+sinA) = (1+cosA+sinA)² ÷ (1+cosA)² -sinA² = 1+cos²A + sin²A + 2cosA + 2sinA + 2sinAcosA ÷ 1+cos²A + 2cosA - sin²A =2+2cosA + 2sinA + 2sinAcosA÷ 2cos²A +2cosA =(1+cosA) + sinA(1+cosA) ÷ cosA(cosA+1) = (1+cosA)(1+sinA)÷cosA(cos+1) =1+sinA÷cosA

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