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If (1²+2²+3²+4²...........+12²)=650 then what is the …

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If (1²+2²+3²+4²...........+12²)=650 then what is the value of X in (2²+4²+6²+8².........+24²)=X.

Posted by Lucifer ? Morningstar? 6 years ago

CBSE > Class 10 > Mathematics

3 answers

Aadya Singh ? 6 years ago

(2^2 + 4^2 + 6^2 + ........+24^2 ) = x
=> 2^2 ( 1^2 + 2^2 + 3^2 +......12^2) = x
=> 4×650
=>2600

Lucifer ? Morningstar? 6 years ago

How

Aadya Singh ? 6 years ago

x = 2,600.

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