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find the equation of the line …

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find the equation of the line which is passing through the point (-2, -4) and perpendicular to the line 3x – y + 5 = 0.

    • Posted by Sahil Kumar 6 years ago

    CBSE > Class 11 > Mathematics
    • 1 answers

    Lucky Papa 6 years ago

    First We Find Slope of Eq. 3x-y+5=0 Y=3x+5 M1=3 For Perpendicular, M1.M2=-1 M2=-1/3, So, Eq. of line..... (Y-Y1)=M2 (X-X2) (Y-(-4))=-1/3 (X-(-2)) 3Y+12=-X-2 X+3Y+14=0... this is req. Eq.

    3Thank You

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