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(sinA + cosecA)2 + (cosA + …

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(sinA + cosecA)2 + (cosA + secA)2 =7+tan2A + cot2A
  • 1 answers

Deepak S 5 years, 11 months ago

LHS=>(sin2A+cosec2A+2×sinA×1/sinA) +(cos2A+sec2A+2×cosA×1/cosA) (sin2A+cosec2A+2+cos2A+sec2A+2) =(sin2A+cos2A)+(1+tan2A)+(1+cot2A)+2+2 1+1+1+4+tan2A+cot2A 7+tan2A+cot2A LHS=RHS Hence proved
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