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(1-cos A)(1+cos A)(1+cos²A)=1

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(1-cos A)(1+cos A)(1+cos²A)=1
  • 2 answers

Swati Agarwal 5 years, 8 months ago

And the solution is Taking LHS : Using identity (a-b) (a+b) =(a² - b²) ( 1-Cos²A)( 1 + Cot²A) As we know: [1 - Cos² A = Sin²A 1 + Cot²A = Cosec²A] identity Now, on putting the values, we have ( Sin²A ) ( Cosec²A) [Sin²A = 1/ Cosec²A] identity =1 =RHS PROVED

Swati Agarwal 5 years, 8 months ago

I think it should be ( 1 - CosA )( 1 + CosA)( 1 + Cot²A)=1
http://mycbseguide.com/examin8/

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