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Cot theta -tan theta =2cos² theta-1/sin …

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Cot theta -tan theta =2cos² theta-1/sin theta cos theta

Posted by Lucifer ? Morningstar? 6 years ago

CBSE > Class 10 > Mathematics

2 answers

Aashish Gaurav 6 years ago

Cos theta / sin theta - sin theta/ cos theta = (Cos ^ theta - sin^ theta )/sin theta cos theta =[cos^ theta -(1- sin^ theta)] / sin theta cos theta = (2 cos^ theta -1)/ sin theta cos theta

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Aashish Gaurav 6 years ago

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sin60° cos 30°+ cos60° sin 30°

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CBSE > Class 10 > Mathematics