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Find two consecutive positive integers sum …

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Find two consecutive positive integers sum of whose square is 365
  • 3 answers

Yogita Ingle 6 years ago

Let the two consecutive integers be x and x + 1.
Then according to the question, we have:

x2 + (x + 1)2 = 365

⇒ x2 + x2 + 2x + 1 - 365 = 0

⇒ 2x2 + 2x - 364 = 0

⇒ 2(x2 + x - 182) = 0

⇒x2 + x - 182 = 0

⇒x2 + 14x - 13x - 182 = 0

  ⇒ (x + 14) (x - 13) = 0

⇒ x = -14 or x = 13

Since the integers are positive, so neglecting x = -14 , we have x = 12.

Hence 13, 14 are two consecutive positive integers.

Nivesh Rawat 6 years ago

Thanks??

Aadya Singh ? 6 years ago

14 and 13.
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