If perimeter of rhombus is 20 …
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Posted by Amit Singh 4 years, 10 months ago
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Yogita Ingle 4 years, 10 months ago
Given, Perimeter of a rhombus = 20 cm
Perimeter of a rhombus = 4×side
Hence, side = 20/4 = 5 cm.
Now, we know that the diagonals of a rhombus bisect each other at right angles (90 degree).
Hence 'a right angled triangle can be visualised with 'side' as the hypotenuse'.
diagonal length = 8 cm
Half the length (since diagonal bisects each other) = 8/2 = 4 cm
(d/2)2 + (d1/2)2 = 52
42 + (d1/2)2 = 52
(d1/2)2 = 9
d1/2 = 3
d1 = 3×2 = 6 cm
Hence other diagonal = 6 cm.
Area = 1/2 × d1×d = 1/2 × 8 × 6 = 24 cm2
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