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Prove that (sin theta+1+cos theta)(sin theta-1+cos …

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Prove that (sin theta+1+cos theta)(sin theta-1+cos theta)(sec theta cosec theta)=2
  • 1 answers

Deep Singh 6 years ago

LHS={(sin Φ+cos Φ)+1}{(sin Φ+cos Φ)-1}(sec Φ*cosec Φ)={(sin Φ + cos Φ)^2 -1}(sec Φ*cosec Φ)=(sin^2Φ+cos^2Φ+2sinΦcosΦ-1)(secΦ*cosecΦ)=(2sinΦcosΦ)(1/cosΦsinΦ)=2=RHS
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