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If secA=3/2 find 2cosA - tan^2A/sin^2A

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If secA=3/2 find 2cosA - tan^2A/sin^2A

Posted by Balraj Bhadauria 6 years ago

CBSE > Class 10 > Mathematics

2 answers

Abbinav Tiwari 6 years ago

0Thank You

Raj Patel 6 years ago

SecA=3/2=H/B By Pythagoras theorem, H^2=P^2+B^2 9=P^2+4 P^2=9-4 P^2=5 P=√5 Therefore, According to the question, 2*2/3-(√5/2)^2/(√5/3) 4/3-(5/4)/(5/9) Now by taking LCM u can get the correcy answer!

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CBSE > Class 10 > Mathematics