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Water is flowing at the rate …

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Water is flowing at the rate of 7 metre per second through a circular pipe whose internal diameter is 2 centimetre into a cylindrical tank the radius of whose base is 40 cm determine the increase of water level in half hour
  • 1 answers

Yogita Ingle 6 years ago

Internal diameter of pipe = 2 cm

Internal radius of pipe = 1 cm

radius of base of tank = 40 cm

Speed of water flowing out from pipe = 7 m / sec ={tex} 7\times\frac{100}{\frac{1}{60}}=7\times100\times60=42000\:cm/min{/tex}

Quantity of water flows out from pipe in 1 min = {tex} \pi\times1^2\times42000 cm³{/tex}

Quantity of water flows out from pipe in 30 min = {tex}\pi\times1^2\times42000\times30{/tex}

                                                                                = 3960000 cm³

let H be the height of water level in tank

Quantity of water filled in tank in 30 min = 3960000 cm³

{tex}\pi\times40^2\times H=3960000{/tex}

{tex}H=3960000\times\frac{7}{22\times1600}{/tex}

H=787.5

Therefore, Water level increases to 787.5 cm in half hour.

 

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