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Subba rao started work in 1995at …

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Subba rao started work in 1995at an annual salary of rs 5000 and received an increment of rs 200 each year. In which year did his income reach Rj. 7000 ?

Posted by Gracy Saini 6 years ago

CBSE > Class 10 > Mathematics

2 answers

Achal Moun 6 years ago

2006

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Alex M 6 years ago

Subba rao starting salary = 5000 i. e, a = 5000 Annual incriment = 200 => d = 200 So, A. P = 5000, 5200, 5400,....... So an = 7000 ==> 7000 = a +( n-1) d 5000+ (n-1) 200 =7000 (n-1) 200 = 2000 (n-1) = 10 ==> n = 11 Hence his income will reach 7000 in the year 2006.

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