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In the given figure, in triangle XYZ, DE parallel to YZ, so that the length of sides XD, XE and EZ (in centimeter) are 2.4,3.2& 4.8 respectively then the length of XY (in centimeter) is

Posted by Shreya G 6 years ago

CBSE > Class 10 > Mathematics

3 answers

Aadya Singh ? 6 years ago

XY = 6cm.

6Thank You

Aayush Ghdoliya 6 years ago

This Ans is write or not

3Thank You

Aayush Ghdoliya 6 years ago

Ans is 6 cm In triangle XYZ , DE parallel to YZ therefore BY BPT XD/DY=YE/EZ 2.4/DY=3.2/4.8 BY CROSS MULTIPLICATION 2.4×4.8=3.2×DY 11.52/3.2=DY DY=3.6 cm Now we have to find XY So XY = XD+DY XY=2.4 cm+3.6 cm XY=6.0 Cm

7Thank You

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