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Find two consecutive positive integers sum …

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Find two consecutive positive integers sum of whose squares is 365
  • 1 answers

Aditi .D 6 years ago

let the no. be  x and x+1   then we have x²+(x+1)²=365                      2x²+2x-364=0                      x²+x-182=0                      x²+14x-13x-182=0                      (x+14)(x-13)=0                  That gives x=13 Avoiding negative value                  one number is 13 and other one 14.
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