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Solve equation for x (i) 22x-2x+3+24=0 …

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Solve equation for x

(i) 2^2x-2^x+3+2⁴=0

(ii) 3^2x+4+1=2.3^x+2

Posted by Dipankar Nath 8 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Sahdev Sharma 8 years, 5 months ago

(i) {tex}2^{2x}-2^{x+3}+2^4=0{/tex}

{tex}=> (2^x)^{2}-2^{x}2^{3}+16=0{/tex}

Put 2^x= y

{tex}=> y^2-8y+16=0{/tex}

{tex}=> y^2-4y-4y+16=0{/tex}

{tex}=> y(y-4)-4(y-4)=0{/tex}

=> (y-4)(y-4) = 0

=> y = 4

{tex}=> 2^x= 4{/tex}

=> {tex}2^x= 2^2{/tex}

So value of x = 2

1Thank You

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