Prove that tangent drawn from the …

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Yogita Ingle 6 years, 1 month ago
Given: A circle with centre O; PA and PB are two tangents to the circle drawn from an external point P.
To prove: PA = PB
Construction: Join OA, OB, and OP.
It is known that a tangent at any point of a circle is perpendicular to the radius through the point of contact.
In
OPA and
OPB:
OA = OB (Radii of the same circle)
OP = OP (Common side)
Therefore,
OPA
OPB (RHS congruency criterion)
(Corresponding parts of congruent triangles are equal)
Thus, it is proved that the lengths of the two tangents drawn from an external point to a circle are equal.
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