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Two slits in youngs experiment are …

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Two slits in youngs experiment are 0.02cm apart. The interference fringes for light of wave length 6000A°are formed on a screen 80cm away. Calculate the distance of fifth bright fringe
  • 2 answers

Deepa Shiju 3 years, 5 months ago

1.2cm
in youngs experiment they given us . d=0.0002m π=0.0000006m D=0.8m n=5. then we find x=? we have a formula . nπ=(xd)/D AND GET YOUR ANS
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