Two slits in youngs experiment are …
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Two slits in youngs experiment are 0.02cm apart. The interference fringes for light of wave length 6000A°are formed on a screen 80cm away. Calculate the distance of fifth bright fringe
Posted by Anita Kumari 4 years, 5 months ago
- 2 answers
Kurai Dodiya Gohil 4 years ago
in youngs experiment
they given us .
d=0.0002m
π=0.0000006m
D=0.8m
n=5. then we find x=?
we have a formula . nπ=(xd)/D
AND GET YOUR ANS
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Deepa Shiju 3 years, 5 months ago
1Thank You