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Prove that tanA +sinA/tanA-sinA = secA …

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Prove that tanA +sinA/tanA-sinA = secA +1/secA-1=1+cosA/1- cosA 

  • 1 answers

Rashmi Bajpayee 7 years, 11 months ago

tanA+sinAtanAsinA

= sinAcosA+sinAsinAcosAsinA

= sinA+cosA.sinAsinAcosA.sinA

= sinA(1+cosA)sinA(1cosA)

= 1+cosA1cosA

Proved.

Also, 1+cosA1cosA

= 1+1secA11secA

= secA+1secA1

Proved.

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