Prove that tanA +sinA/tanA-sinA = secA …
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Posted by Aditya Narayan Panda 7 years, 11 months ago
- 1 answers
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Rashmi Bajpayee 7 years, 11 months ago
tanA+sinAtanA−sinA
= sinAcosA+sinAsinAcosA−sinA
= sinA+cosA.sinAsinA−cosA.sinA
= sinA(1+cosA)sinA(1−cosA)
= 1+cosA1−cosA
Proved.
Also, 1+cosA1−cosA
= 1+1secA1−1secA
= secA+1secA−1
Proved.
2Thank You