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Find pairs of natural numbers whose least common multiple is 78 and the greatest divisor is 13

Posted by Soumya Singh 6 years ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years ago

Least common factor (LCM) = 78
Greatest divisor is also a HCF = 13
As, we know , HCF $\times$ LCM = a $\times$ b ( a and b are two natural no. of which LCM and HCF is given)
Therefore, required product of no. = 13 $\times$ 78 = a $\times$ b =1014 or 2 $\times$ 3 $\times$ 13 $\times$ 13
Since 13 is common in both no. as its HCF is 13
Required no.= 13 $\times$ 3 = 39 and 13 $\times$ 2 = 26
$\therefore$ Pairs of natural numbers are 78 and 13 or 26 and 39.

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