Find pairs of natural numbers whose …

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Sia ? 6 years, 5 months ago
Least common factor (LCM) = 78
Greatest divisor is also a HCF = 13
As, we know , HCF {tex}\times{/tex} LCM = a {tex}\times{/tex} b ( a and b are two natural no. of which LCM and HCF is given)
Therefore, required product of no. = 13 {tex}\times{/tex} 78 = a {tex}\times{/tex} b =1014 or 2{tex}\times{/tex}3{tex}\times{/tex}13{tex}\times{/tex}13
Since 13 is common in both no. as its HCF is 13
Required no.= 13{tex}\times{/tex}3 = 39 and 13 {tex}\times{/tex}2 = 26
{tex}\therefore{/tex} Pairs of natural numbers are 78 and 13 or 26 and 39.
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