If 3x=cosec thita and 3/x=cot thita, …
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Sia ? 6 years, 5 months ago
We know that
{tex}\cos e c ^ { 2 } \theta - \cot ^ { 2 } \theta = 1{/tex}
{tex}\Rightarrow ( 3 x ) ^ { 2 } - \left( \frac { 3 } { x } \right) ^ { 2 } = 1{/tex}
{tex}\Rightarrow 9 x ^ { 2 } - \frac { 9 } { x ^ { 2 } } = 1{/tex}
{tex}\Rightarrow 3 \times 3 \left( x ^ { 2 } - \frac { 1 } { x ^ { 2 } } \right) = 1{/tex}
{tex}\Rightarrow 3 \left( x ^ { 2 } - \frac { 1 } { x ^ { 2 } } \right) = \frac { 1 } { 3 }{/tex}
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