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(sinA+cosecA)2+(cosA+secA)2=7+tan2A+cot2A

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(sinA+cosecA)2+(cosA+secA)2=7+tan2A+cot2A

    • Posted by Anshika Shrivastava 5 years, 9 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Jay Kumar Sharma 5 years, 9 months ago

    Taking LHS (SinA+CosecA)²+(CosA+SecA)² =Sin²A+Cosec²A+2sinAcosecA+Cos²A+2cosAsecA+sec²A =Sin²A+Cos²A+Cosec²A+Sec²A+2cosAsecA+2sinAcosecA =1+1+cot²A+1+tan²A+2cosA*1/cosA+2sinA*1/sinA =2+2+2+1+tan²A+cot²A =7+tan²A+cot²A

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