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The sum of the areas of …

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The sum of the areas of two squares is 640m square .if the difference of their perimeters is 64m find the slides of the square.

    • Posted by Jagat Limboo 6 years, 4 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Sahil ??? 6 years, 4 months ago

    Sides of square are 24 and 8.

    0Thank You

    Gaurav Seth 6 years, 4 months ago

    Let the side of one square be x

    Perimeter of this square = 4x

    Given, Difference of perimeter of 2 squares = 64 m

    Thus, Perimeter of the other square = (64 + 4x) m  

    And, each side of this second square =  = (16 +x) m

    According to the problem, sum of the areas of two squares is 640 

    Since side of a square cannot be negative, each side of the square = 8 m.

    And, each side of second square = (16+8) m = 24 m

    1Thank You

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