An aeroplane went 3000m high passes …

Given:

The aeroplane when 3000 m high passes vertically above another aeroplane.  

Angle of elevation of the aeroplane’s at the same observation = 60°and 45°

To find:

How much high is the one plane to other = ?

Solution:

The height at which the aeroplane (1) is from the ground is of height = 3000m.

The observer is standing at point A from where he observe both the planes one at D and another at C

The height at which the aeroplane (2) is from the ground is of height = h meters.

To find the height difference between the two planes, we first have to find the height of the second plane

The angle for the second plane is 45, which means

Now equating the value of the length between the planes and the observer

The height of the second plane from the ground is 1732m

Therefore, the Distance between the planes or the second plane is (3000 – 1732) = 1268 m lower than the first plane,

The height that the first plane is from second plane is 1268 m.