Trignometric identities

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Yogita Ingle 6 years, 1 month ago
For the right triangle ABC, let 0°≤ A ≤ 90°
1) cos2 A + sin2 A = 1.
2) cos2 A =1 - sin2 A.
3) sin2 A =1 - cos2 A.
4) sec2 A - tan2 A = 1.
5) 1 + tan2 A = sec2 A.
6) tan2 A = sec2 A – 1.
7) cosec2 A - cot2 A = 1.
8) cot2 A + 1 = cosec2 A.
9) cot2 A = cosec2 A – 1 .
10) sec A - tan A = 1/ sec A + tan A
11) cosec A - cot A = 1/ cosec A + cot A
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