Prove that the path of a …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by S Eshita 6 years, 2 months ago
- 1 answers
Test
Related Questions
Posted by M D 1 year, 4 months ago
- 1 answers
Posted by Mansi Class 9Th 1 year, 5 months ago
- 0 answers
Posted by Nekita Baraily 1 year, 5 months ago
- 2 answers
Posted by Mohammed Javith 1 year, 5 months ago
- 0 answers
Posted by Pankaj Tripathi 1 year, 5 months ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Gaurav Seth 6 years, 2 months ago
Let a body is projected with speed u m/s inclined θ with horizontal line .
Then, vertical component of u, = ucosθ
Horizontal component of u , = usinθ
acceleration on horizontal, ax = 0
acceleration on vertical, ay = -g
Now, use formula ,
x =
x = ucosθ.t
t = x/ucosθ------(1)
Again, y =
y = usinθt - 1/2gt²
Put equation (1) here,
y = usinθ × x/ucosθ - 1/2g × x²/u²cos²θ
= tanθx - 1/2gx²/u²cos²θ
This equation is similar to Standard equation of parabola y = ax² + bx + c her, a, b and c are constant
So, A projectile motion is parabolic motion
2Thank You