A train 200m long crosses a …
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Sahdev Sharma 8 years, 5 months ago
Total distance S = 200+300= 500m
Initial velocity u = 3m/s
Final velocity v = 5 m/s
We know,
v2-u2 = 2as
=> 25-9= 1000a
=> a = {tex}{16\over 1000} m/s^2{/tex}
Again
v = u +at
=> 5 = 3+{tex}{16\over 1000}t{/tex}
=> t = {tex}{2\times 1000\over 16 }= 125s = 2 \ minutes \ 5 \ second{/tex}
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