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3x- 4y+22=0 and 4x-3y+13 by substitution

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3x- 4y+22=0 and 4x-3y+13 by substitution

Posted by Tanay Sarda 6 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Harikesh Singh 6 years, 2 months ago

3x-4y+22=0....eq(1) 4x-3y+13=0.....eq(2) From eq(1) x=(-22+4y)/3...eq(3) By putting value of x in eq(2),we get 4x-3y+13=0 4(-22+4y/3)-3y+13=0 (-88+16y-9y+39)/3=0 -49+7y=0 7y=49 y=7 Putting value of y in eq(3),we get x=(-22+4*7)/3 x=(-22+28)/3 x=2 Hence,x=2 and y=7

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CBSE > Class 10 > Mathematics