A large fluid star ossilates in …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
A large fluid star ossilates in shape under the abundance of its own gravitational field.Using dimensional analysis find the expression for period of oscillation (T) in terms of radius of star (R),mean density of fluid (p) and gravitational constant (G)
Posted by Mehul Sharma 6 years, 2 months ago
- 1 answers
Test
Related Questions
Posted by Nekita Baraily 1 year, 5 months ago
- 2 answers
Posted by Mohammed Javith 1 year, 5 months ago
- 0 answers
Posted by Mansi Class 9Th 1 year, 5 months ago
- 0 answers
Posted by M D 1 year, 4 months ago
- 1 answers
Posted by Pankaj Tripathi 1 year, 5 months ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 6 years, 2 months ago
Let the period of oscillation T of a large fluid star depends on the radius of star, R, the mean density of fluid, {tex}\rho{/tex} and universal gravitational constant, G as:
T = k Ra {tex}\rho{/tex}b Gc, where k is a dimensionless constant and a, b, c are their exponents.
Now, equating the dimensions on both the sides, we have,
[Mo Lo T1] = [L]a [M L-3]b [M-1 L3 T-2]c = Mb-c La-3b+3c T-2c
On comparing powers of M, L and T on both sides, we get,
b - c = 0 ...(i)
a - 3b + 3c = 0 ...(ii)
and - 2c = 1 ...(iii)
On simplifying these equations, we get c = {tex}-\frac{1}{2}{/tex}, b = {tex}-\frac{1}{2}{/tex} and a = 0
Thus, period of oscillation, T = {tex}k \rho^{-\frac{1}{2}} G^{-\frac{1}{2}}{/tex}= {tex}\frac{k}{\sqrt{\rho G}}{/tex}
This is the required expression.
0Thank You