Sinthita - costhita + 1 ÷ …
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Rashmi Bajpayee 7 years, 11 months ago
L.H.S. = sinθ−cosθ+1sinθ+cosθ−1
Dividing all terms by cosθ
= tanθ−1+secθtanθ+1−secθ
= tanθ+secθ−1tanθ−secθ+1
= tanθ+secθ−(sec2θ−tan2θ)tanθ−secθ+1
= tanθ+secθ−(secθ+tanθ)(secθ−tanθ)tanθ−secθ+1
= (tanθ+secθ)(1−secθ+tanθ)tanθ−secθ+1
= secθ+tanθ
= secθ+tanθ×secθ−tanθsecθ−tanθ
= sec2θ−tan2θsecθ−tanθ
= 1secθ−tanθ
= R.H.S.
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