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Sinthita - costhita + 1 ÷ …

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Sinthita - costhita + 1 ÷ sinthita + costhita - 1 = 1 ÷ secthita - tanthita

  • 1 answers

Rashmi Bajpayee 7 years, 11 months ago

L.H.S. = sinθcosθ+1sinθ+cosθ1

Dividing all terms by cosθ

= tanθ1+secθtanθ+1secθ

= tanθ+secθ1tanθsecθ+1

= tanθ+secθ(sec2θtan2θ)tanθsecθ+1

= tanθ+secθ(secθ+tanθ)(secθtanθ)tanθsecθ+1

= (tanθ+secθ)(1secθ+tanθ)tanθsecθ+1

= secθ+tanθ

= secθ+tanθ×secθtanθsecθtanθ

= sec2θtan2θsecθtanθ

= 1secθtanθ

= R.H.S.

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