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in figure ABCD is a rectangle inscribed in a quadrant of a circle of radius 10 centimetre if 2 root 5 find the area of the rectangle

Posted by Karan Singh 5 years, 6 months ago

CBSE > Class 09 > Mathematics

2 answers

Sia ? 5 years, 6 months ago

We have, AC = 10 cm and AD = 2 $\sqrt{5}$ cm
$\therefore$ AC² = AD² + CD²
$\Rightarrow$ CD = $\sqrt{AC^2 - AD^2}$ = $\sqrt{(10)^{2}-(2 \sqrt{5})^{2}}$ = 4 $\sqrt{5}$ cm
$\therefore$ ar(rect ABCE) = AD $\times$ CD = 2 $\sqrt{5}$ $\times$ 4 $\sqrt{5}$ cm²
= 8 $\times$ 5 cm² = 40 cm²

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CBSE > Class 09 > Mathematics