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If one zero of the polynomial (a^2+9)x^2+13x+6a is reciprocal of the other. Find the value of a

Posted by Akhil Chaturvedi 6 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Anushree The Topper Student Mohanram 6 years, 2 months ago

sum of roots = m + 1/m = -13/(a^2+9) and product of the roots = m x 1/m = 6a which gives 6a / (a^2+9)=1 6a = a^2+9 a^2-6a+9=0 implies a^2-2 (a) (3) + 3^2=0 thus (a-3)^2=0 this a-3=0 and finally the value of a = 3

1Thank You

Anushree The Topper Student Mohanram 6 years, 2 months ago

Let m and 1/m be the roots given roots are reciprocal of each other

0Thank You

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