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In the adjoining figure, ABCD is …

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In the adjoining figure, ABCD is a trap. in which AB// DC; AB=7 cm ; AD=BC= 5 cm and the distance between AB and DC is 4 cm. Find the length of DC and hence, find the area of trap. ABCD.

    • Posted by Shivam Shaw 5 years ago

    CBSE > Class 09 > Mathematics
    • 2 answers

    Ruuzcee Zimik 5 years ago

    DC =1 Area=19

    0Thank You

    Yogita Ingle 5 years ago

    To start off with, we have to draw perpendiculars from A and B on CD at E and F respectively.

    Now, we will obtain two right-angled triangles.

    We apply Pythagoras Theorem in both of them:-

    DE² = AD² - AE²

    DE² = 5² - 4²

    DE² = 25 - 16

    DE² = 9

    DE = √9

    DE = 3 cm

    Similarly, FC = 3 cm

    DC can be re-written as:-

    =DE + EF + FC (Also, EF = AB as ABEF forms a rectangle)

    =3 + 7 + 3

    = 13cm

    So, the value of x is 13cm

    1Thank You

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