In the adjoining figure, ABCD is …

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In the adjoining figure, ABCD is a trap. in which AB// DC; AB=7 cm ; AD=BC= 5 cm and the distance between AB and DC is 4 cm. Find the length of DC and hence, find the area of trap. ABCD.

Posted by Shivam Shaw 5 years, 4 months ago

CBSE > Class 09 > Mathematics

2 answers

Ruuzcee Zimik 5 years, 4 months ago

DC =1 Area=19

0Thank You

Yogita Ingle 5 years, 4 months ago

To start off with, we have to draw perpendiculars from A and B on CD at E and F respectively.

Now, we will obtain two right-angled triangles.

We apply Pythagoras Theorem in both of them:-

DE² = AD² - AE²

DE² = 5² - 4²

DE² = 25 - 16

DE² = 9

DE = √9

DE = 3 cm

Similarly, FC = 3 cm

DC can be re-written as:-

=DE + EF + FC (Also, EF = AB as ABEF forms a rectangle)

=3 + 7 + 3

= 13cm

So, the value of x is 13cm

1Thank You

ANSWER

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CBSE > Class 09 > Mathematics