If p, q are zeroes of …
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Sia ? 6 years ago
According to the question, p and q are the zeroes of polynomial f(x) = 2x2 - 7x + 3,
f(x) = 2x2 -7x + 3
Sum of roots = p + q = − Coefficient of x Coefficient of x2
=−(−72)=72
Product of roots= pq = Constant term Coefficient of x2=32
Since, (p + q)2 =p2 + q2 + 2pq
So, p2 + q2 = (p + q)2 - 2pq
=(72)2−3=494−31=374
Hence, the value of p2+ q2=374
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