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The no. Of real roots of …

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The no. Of real roots of the equation (X-1)*2+ (X-2)*2 +(x -3)*2=0 is. Please explain this.

    • Posted by Husita Patel 6 years, 2 months ago

    CBSE > Class 10 > Mathematics
    • 3 answers

    Lalit Mohan 6 years, 2 months ago

    One zero Because degree of polynomial is 1

    1Thank You

    Mansi Kumari 6 years, 2 months ago

    Answer is x=2 2x-2+2x-4+2x-6 6x-12=0 6(x-2)=0 x-2=0 X=2

    1Thank You

    Aadya Singh ? 6 years, 2 months ago

    (x-1)^2 + (x-2)^2+(x-3)^2 =0 => 3x^2 -12x +14 = 0 . Now, D = b^2 - 4ac => (-12)^2 - 4×3×14 => 144 - 168 => -24 . Since the discriminant is less than 0 . Therefore, it has zero real root.

    2Thank You

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    Posted by Hari Anand 6 months, 2 weeks ago

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