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Ch6 ex.6.4 ques.7

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Ch6 ex.6.4 ques.7

    • Posted by Rajeev Kumar Singh 6 years, 2 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Ram Kushwah 6 years, 2 months ago

    We know that area of an equilateral triangle with side a

    ={tex}\sqrt3{/tex} a2/4

    now let side of square =x

    then area of equilateral triangle on one side

    A1={tex}\sqrt3{/tex} x2/4--------------------------(1)

    If length of diagonal is d then

    d2=x2+x2=2x2

    area of equilateral traingle at diagonal

    A2=={tex}\sqrt3{/tex} *2x2/4

    =2*({tex}\sqrt3{/tex} a2/4)

    =2A1

    hence proved

     

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