If a transversal intersect two LINE'S …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Test
Related Questions
Posted by Alvin Thomas 3 months ago
- 0 answers
Posted by Yash Pandey 6 months, 1 week ago
- 0 answers
Posted by Akhilesh Patidar 1 year, 4 months ago
- 0 answers
Posted by Duruvan Sivan 6 months, 1 week ago
- 0 answers
Posted by Sheikh Alfaz 1 month, 2 weeks ago
- 0 answers
Posted by Savitha Savitha 1 year, 4 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 6 years, 2 months ago
In figure,
transversal AD intersects two lines
PQ and RS at point B and C respectively.
Ray BE is the bisector of {tex}\angle BACQ{/tex}
So, {tex}\angle \mathrm{ABE}=\angle \mathrm{EBQ}=\frac{1}{2}(\angle \mathrm{ABQ}){/tex}
and ray CG is the bisector of {tex}\angle \mathrm{BCS}{/tex};
and {tex}B E \| C G{/tex}
We have to prove {tex}\mathrm{PQ} \| \mathrm{RS}{/tex}
Since {tex}\mathrm{BE} \| \mathrm{ CG}{/tex}
& line AD is a transversal
{tex}\angle \mathrm{ABE}=\angle \mathrm{BCG}{/tex} (Corresponding angles are equal)
{tex}\frac{1}{2}(\angle \mathrm{ABQ})=\frac{1}{2}(\angle \mathrm{BCS}){/tex}
{tex}\angle \mathrm{ABQ}=\angle \mathrm{BCS}{/tex}
But, these angles are the corresponding angles formed by transversal AD with PQ and RS
2Thank You