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Solve : xSin3 theta + yCos …

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Solve : xSin3 theta + yCos theta = Sin theta Cos theta and x Sin theta = yCos theta . prove x2 + y2 = 1 . 2 is square and 3 is cube .
  • 2 answers

Sukhpreet Singh 6 years, 2 months ago

Ok

Chahat Karia 6 years, 2 months ago

As x sin theta = y cos theta x sin3 theta + y cos theta = sin theta cos theta Sin2 theta + 1 =sin theta cos theta Cos2 theta= sin theta cos theta Cos2 theta/ cos theta = sin theta Cos theta = sin theta Therefore, sin2 theta = cos2 theta x sin theta = y cos theta x cos( 90° - theta) = y cos theta therefore x= y Also, x2 = y2 And if they are equal their sum will be 1 therefore, x2+y2=1 (Tho not sure if it is correct, just helpin dude)
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