How far away from the surface …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by Mohammed Javith 1 year, 3 months ago
- 0 answers
Posted by Nekita Baraily 1 year, 2 months ago
- 2 answers
Posted by Mansi Class 9Th 1 year, 2 months ago
- 0 answers
Posted by Pankaj Tripathi 1 year, 2 months ago
- 1 answers
Posted by M D 1 year, 2 months ago
- 1 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 6 years ago
We know that acceleration due to gravity from the surface of Earth at height "h" is given as,
{tex}g' = g \left( \frac { R } { R + h } \right) ^ { 2 }{/tex}
reduced to 4% of gravity due to earth g' = 4% of {tex}g' = \frac { 4 g } { 100 }{/tex}
R = 6400km
{tex}\frac { 4 g } { 100 }= g \left( \frac { R } { R + h } \right) ^ { 2 }{/tex}
{tex}\frac { 4 } { 100 } = \left( \frac { R } { R + h } \right) ^ { 2 }{/tex}
{tex}\frac { 2 } { 10 } = \frac { R } { R + h }{/tex}
2(R + h) = 10R
2R+2h=10R
2h =10R-2R
2h=8R
h=8R/2
h = 4R
h= 4 {tex}\times{/tex} 6400
h= 25,600km.
1Thank You