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A and B are friends and their ages differ by 2 years. A's father D is twice as old as A and B is twice as old as his sister C. The age of D and C differ by 40years. Find the ages of A and B.?(R.D. Sharma ques)

Posted by ?❤Armààñ Màlík'S Fàñ❤? 6 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

?❤Armààñ Màlík'S Fàñ❤? 6 years, 2 months ago

Thanks?

1Thank You

Gaurav Seth 6 years, 2 months ago

Let the age of A = x

age of B = x+2

since, A's father D is twice as old as A
So, age of D = 2×x = 2x

and since B is twice as old as his sister
So, age of C = age of B / 2 = (x+2)/2

according to the question,
The ages of D and C differ by 40yrs.
it means,

age of D - age of C = 40

=> 2x - [(x+2)/2] = 40

=> 2x - (x+2)/2 = 40

=> 4x/2 - (x+2)/2 = 40

=> (4x - x + 2)/2 = 40

=> 3x+2/2 = 40

=> 3x + 2 = 40 × 2

=> 3x = 80 - 2

=> x = 78/3
= 26
So, age of A = x = 26 years

age of B = x + 2 = 26 + 2 = 28 years

2Thank You

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