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Construct a triangle ABCin which BC=7cm, …

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Construct a triangle ABCin which BC=7cm, angle B=75 and AB+AC=13cm

Posted by Bindu Tr 6 years, 2 months ago

CBSE > Class 09 > Mathematics

2 answers

Bindu Tr 6 years, 2 months ago

Thc

1Thank You

Gaurav Seth 6 years, 2 months ago

Given : Base BC = 7cm, angle B = 75° and sum of two sides AB + AC = 13 cm.

Required : To Construct ∆ABC

STEPS OF CONSTRUCTION :

1. Draw a ray BX and cut off a line segment BC = 7cm; from it.

2. At B; construct angle YBX = 75°

3. With B as centre and radius = 13 cm (because AB + AC = 13cm) draw an arc to meet BY at D.

4. Join CD

5. Draw Perpendicular bisector PQ of CD intersecting BD at A.

6. Join AC

Then ABC is the required triangle.

A lies on perpendicular bisector of CD.

Therefore, AC = AD

=> AB = BD - AD

=> AB = BD - AC

=> AB + AC = BD = 13cm

3Thank You

ANSWER

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