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The sum of the digits of …

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The sum of the digits of a two digit number is 9.also,nine times this number is twice the number obtained by reversing the order of the digits. Find the number
  • 5 answers

Harsh Mishra 6 years, 2 months ago

Answer Copied From www.brainly.com 

 

mayank1524  Expert
Let unit digit  = x

Tens digit  = y

Number will 10 times the tens digit + unit times the unit digit

Hence number will 10 y + x

Sum of digits are 9

So that

X + y  = 9        ………….(1)

 nine times this number is twice the number obtained by reversing the order of the digits


9 (10 y + x )  =  2 (10 x + y )

90 y + 9 x  = 20 x + 2y

88 y – 11 x  = 0

Divide by 11 we get

8 y  - x  = 0     …………..(2)

X + y  = 9        ………….(1)


Adding both equations we get

9 y = 9

Y = 9/9 = 1

Plug this value in equation first we get

X+ y = 9

X + 1 = 9

X = 8

So our original number is 10 y  + x    = 10*1 + 8 = 18

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Chirag Aggarwal 6 years, 2 months ago

Let tens digit of a no. be= x the ones digit be= y Therefore, the no. Is =10x+y Reversing no. =10y+x Case 1 x+y=9.....(1) Case 2 9(10x+y)=2(10y+x) 90x+9y=20y+2x 90x-2x=20y-9y 88x=11y 88x-11y=0 Divide the eq by 11 8x-y=0......(2) From eq. (1) and (2) x+y=9 8x-y=0 ------------ 9x=9 x=9|9 x=1 From eq. (1) x+y=9 1+y=9 Y=9-1 Y=8 Therefore no. Is =10x+y =10×1+8 =18 Reversing no.=81

Manak Fangirl 6 years, 2 months ago

Number =18

Anantjeet Singh 6 years, 2 months ago

The no.is 18.

Abhijeet Ghule 6 years, 2 months ago

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