Show that in a right angled …
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Sia ? 5 years, 1 month ago
Let {tex}\triangle{/tex}ABC be a right angled triangle in which {tex}\therefore{/tex}B = 90o
Then {tex}\angle{/tex}A + {tex}\angle{/tex}C = 90o . . . .[sum of three angles of a triangle]
{tex}\therefore{/tex} {tex}\angle{/tex}B = {tex}\angle{/tex}A + {tex}\angle{/tex}C
{tex}\therefore{/tex} {tex}\angle{/tex}B > {tex}\angle{/tex}A
and {tex}\angle{/tex}B > {tex}\angle{/tex}C
{tex}\therefore{/tex} AC > BC . . . [Side opposite to greater angle is longer]
and AC > AB
{tex}\therefore{/tex} AC is the longest side, i.e. hypotenuse is the longest side.
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